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0.00025 BCH Anyone good at statistics/Math? What are the probabilities to win this lottery odds?

Pick 4 numbers from 1 to 14. And get both 4 numbers at the exact position. For example 1 , 14, 12 , 9 Please explain how you got the odds. Formula used. Thanks

tonyuk932 4 months ago
Tags:
• Probability
• Maths
• Lottery ##### kimo2 4 months ago Correct
4 numbers from 1 to 14 give 14^4=38416 combinations.
So, there are 1 combination we need and 38415 wrong combinations.
Probability that 1 combination will occur is 1/38416.
Probability that a wrong combination will occur is 38415/38416.
The odds = probability that event will occur / probability that event will not occur = (1/38416) / (38415/38416) = 1/38415.
##### tonyuk932 4 months ago
Thanks, want to check something and will mark it later tonight as correct.
##### szpszp 4 months ago
The odds = probability that event will occur / probability that event will not occur = (1/38416) / (38415/38416) = 1/38415. There is no such formula in mathematics.

I had to write because I thought the math was done wrong, the answer is wrong. Everything is correct, the number written as the last answer is wrong.

Hi buddy,
Pick 4 items from a larger set ={1,2,3,4,5,6,7...14}:
example results could be: {6,2,7,4} or {5,3,14,2} .. etc
Suppose you have 4 spots:
_ _ _ _
The first spot have 14 items available:
14_ _ _
Since you took one item from the bigger set, the next spot only will have 13 options:
14 13 _ _
And so on:

14 13 12 11.

To obtain the total ways you could arrange the numbers is:

14 * 13 * 12 * 11 = 24024

With the total number of permutations you could now calculate the odds :
1 / 24024.

The formula is
N!
-------------.
(N - r)!

Where n, is the total number of items in the set (14) and r, the number of ways the items coul be arranger (4)

14! / (14-4)! = 14! / 10 ! = 14 * 13 *12 *11
Well in order to be precise, if you are expecting results in your set such as { 2, 2, 4, 6} the kimo2 response is correct. If the numbers should not be repeated such as {3,4,7,12} then my response is the correct one
##### tonyuk932 4 months ago
Yes, kimo2 seems to be correct. Loved your effort explaining it. Perhaps another time, will mark yours as correct on another one.
38415.
##### Esma 4 months ago
First of all, we need to count the total number of ways 4 numbers
can be formed which means we need to compute the combination.
The number of possible outcomes of the numbers drawing is 14C4.

14C4 = 14 * 13 * 12 * 11
______________
4 * 3 * 2 * 1

= 24, 024
_________
24

= 1001 combinations

Of these 1001 possible outcomes, only one would match all 4 numbers at the exact position. So the probability is 1 : 1001 = 0.00099900099
The chance is < than 1%
1:38415
##### Aldo Colombo 4 months ago
kimo2 is correct, esma is wrong, srada is also wrong, as you say pick 4 numbers from 1 to 14, you don't say a number cannot be repeated.
##### tonyuk932 4 months ago
Yes, I will reward kimo2
##### Hassan Bilyaminu 4 months ago
4 numbers ranging from 1 to 14 is given as 14^4=38416 combinations.
Therefore there are 1 combination we need and 38415 wrong combinations.
Probability that 1 combination will occur is 1/38416.
Probability that a wrong combination will occur is 38415/38416.
The odds = probability that event will occur / probability that event will not occur = (1/38416) / (38415/38416) = 1/38415.
##### Danijela Kazanovic 4 months ago
2 4 6 8 posibiliti 1:56000
##### Joshua 4 months ago
The odds are 1 in 245,000,000
##### Joshua 4 months ago
The odds are 1 in 245,000,000
##### Busila Andrei 4 months ago
14*13*12*11=24024
##### szpszp 4 months ago
if each number will be used only once in a set
It becomes 14 * 13 * 12 * 11 = 24024.
The probability of the lottery out is 1/24024.

if each number will be used more than once in a set
It becomes 14 * 14 * 14 * 14 = 38416.
The probability of the lottery out is 1/38416.
##### priyank5729 4 months ago
https://cryptotabbrowser.com/19322042