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Anyone good at statistics/Math? What are the probabilities to win this lottery odds?

Pick 4 numbers from 1 to 14. And get both 4 numbers at the exact position. For example 1 , 14, 12 , 9 Please explain how you got the odds. Formula used. Thanks

4 numbers from 1 to 14 give 14^4=38416 combinations.

So, there are 1 combination we need and 38415 wrong combinations.

Probability that 1 combination will occur is 1/38416.

Probability that a wrong combination will occur is 38415/38416.

The odds = probability that event will occur / probability that event will not occur = (1/38416) / (38415/38416) = 1/38415.

So, the answer is 1:38415.

So, there are 1 combination we need and 38415 wrong combinations.

Probability that 1 combination will occur is 1/38416.

Probability that a wrong combination will occur is 38415/38416.

The odds = probability that event will occur / probability that event will not occur = (1/38416) / (38415/38416) = 1/38415.

So, the answer is 1:38415.

Thanks, want to check something and will mark it later tonight as correct.

The odds = probability that event will occur / probability that event will not occur = (1/38416) / (38415/38416) = 1/38415. There is no such formula in mathematics.

I had to write because I thought the math was done wrong, the answer is wrong. Everything is correct, the number written as the last answer is wrong.

So, the answer is 1:38416

I had to write because I thought the math was done wrong, the answer is wrong. Everything is correct, the number written as the last answer is wrong.

So, the answer is 1:38416

Hi buddy,

Pick 4 items from a larger set ={1,2,3,4,5,6,7...14}:

example results could be: {6,2,7,4} or {5,3,14,2} .. etc

Suppose you have 4 spots:

_ _ _ _

The first spot have 14 items available:

14_ _ _

Since you took one item from the bigger set, the next spot only will have 13 options:

14 13 _ _

And so on:

14 13 12 11.

To obtain the total ways you could arrange the numbers is:

14 * 13 * 12 * 11 = 24024

With the total number of permutations you could now calculate the odds :

1 / 24024.

The formula is

N!

-------------.

(N - r)!

Where n, is the total number of items in the set (14) and r, the number of ways the items coul be arranger (4)

14! / (14-4)! = 14! / 10 ! = 14 * 13 *12 *11

Pick 4 items from a larger set ={1,2,3,4,5,6,7...14}:

example results could be: {6,2,7,4} or {5,3,14,2} .. etc

Suppose you have 4 spots:

_ _ _ _

The first spot have 14 items available:

14_ _ _

Since you took one item from the bigger set, the next spot only will have 13 options:

14 13 _ _

And so on:

14 13 12 11.

To obtain the total ways you could arrange the numbers is:

14 * 13 * 12 * 11 = 24024

With the total number of permutations you could now calculate the odds :

1 / 24024.

The formula is

N!

-------------.

(N - r)!

Where n, is the total number of items in the set (14) and r, the number of ways the items coul be arranger (4)

14! / (14-4)! = 14! / 10 ! = 14 * 13 *12 *11

Well in order to be precise, if you are expecting results in your set such as { 2, 2, 4, 6} the kimo2 response is correct. If the numbers should not be repeated such as {3,4,7,12} then my response is the correct one

Yes, kimo2 seems to be correct. Loved your effort explaining it. Perhaps another time, will mark yours as correct on another one.

38415.

First of all, we need to count the total number of ways 4 numbers

can be formed which means we need to compute the combination.

The number of possible outcomes of the numbers drawing is 14C4.

14C4 = 14 * 13 * 12 * 11

______________

4 * 3 * 2 * 1

= 24, 024

_________

24

= 1001 combinations

Of these 1001 possible outcomes, only one would match all 4 numbers at the exact position. So the probability is 1 : 1001 = 0.00099900099

The chance is < than 1%

can be formed which means we need to compute the combination.

The number of possible outcomes of the numbers drawing is 14C4.

14C4 = 14 * 13 * 12 * 11

______________

4 * 3 * 2 * 1

= 24, 024

_________

24

= 1001 combinations

Of these 1001 possible outcomes, only one would match all 4 numbers at the exact position. So the probability is 1 : 1001 = 0.00099900099

The chance is < than 1%

1:38415

kimo2 is correct, esma is wrong, srada is also wrong, as you say pick 4 numbers from 1 to 14, you don't say a number cannot be repeated.

Yes, I will reward kimo2

4 numbers ranging from 1 to 14 is given as 14^4=38416 combinations.

Therefore there are 1 combination we need and 38415 wrong combinations.

Probability that 1 combination will occur is 1/38416.

Probability that a wrong combination will occur is 38415/38416.

The odds = probability that event will occur / probability that event will not occur = (1/38416) / (38415/38416) = 1/38415.

So, the answer is 1:38415.

Therefore there are 1 combination we need and 38415 wrong combinations.

Probability that 1 combination will occur is 1/38416.

Probability that a wrong combination will occur is 38415/38416.

The odds = probability that event will occur / probability that event will not occur = (1/38416) / (38415/38416) = 1/38415.

So, the answer is 1:38415.

2 4 6 8 posibiliti 1:56000

The odds are 1 in 245,000,000

The odds are 1 in 245,000,000

14*13*12*11=24024

if each number will be used only once in a set

It becomes 14 * 13 * 12 * 11 = 24024.

The probability of the lottery out is 1/24024.

if each number will be used more than once in a set

It becomes 14 * 14 * 14 * 14 = 38416.

The probability of the lottery out is 1/38416.

It becomes 14 * 13 * 12 * 11 = 24024.

The probability of the lottery out is 1/24024.

if each number will be used more than once in a set

It becomes 14 * 14 * 14 * 14 = 38416.

The probability of the lottery out is 1/38416.

https://cryptotabbrowser.com/19322042