4 numbers from 1 to 14 give 14^4=38416 combinations.
So, there are 1 combination we need and 38415 wrong combinations.
Probability that 1 combination will occur is 1/38416.
Probability that a wrong combination will occur is 38415/38416.
The odds = probability that event will occur / probability that event will not occur = (1/38416) / (38415/38416) = 1/38415.
So, the answer is 1:38415.

Hi buddy,
Pick 4 items from a larger set ={1,2,3,4,5,6,7...14}:
example results could be: {6,2,7,4} or {5,3,14,2} .. etc
Suppose you have 4 spots:
_ _ _ _
The first spot have 14 items available:
14_ _ _
Since you took one item from the bigger set, the next spot only will have 13 options:
14 13 _ _
And so on:

14 13 12 11.

To obtain the total ways you could arrange the numbers is:

14 * 13 * 12 * 11 = 24024

With the total number of permutations you could now calculate the odds :
1 / 24024.

The formula is
N!
-------------.
(N - r)!

Where n, is the total number of items in the set (14) and r, the number of ways the items coul be arranger (4)

14! / (14-4)! = 14! / 10 ! = 14 * 13 *12 *11

Well in order to be precise, if you are expecting results in your set such as { 2, 2, 4, 6} the kimo2 response is correct. If the numbers should not be repeated such as {3,4,7,12} then my response is the correct one

38415.

First of all, we need to count the total number of ways 4 numbers
can be formed which means we need to compute the combination.
The number of possible outcomes of the numbers drawing is 14C4.

14C4 = 14 * 13 * 12 * 11
______________
4 * 3 * 2 * 1

= 24, 024
_________
24

= 1001 combinations

Of these 1001 possible outcomes, only one would match all 4 numbers at the exact position. So the probability is 1 : 1001 = 0.00099900099
The chance is < than 1%

1:38415

kimo2 is correct, esma is wrong, srada is also wrong, as you say pick 4 numbers from 1 to 14, you don't say a number cannot be repeated.

4 numbers ranging from 1 to 14 is given as 14^4=38416 combinations.
Therefore there are 1 combination we need and 38415 wrong combinations.
Probability that 1 combination will occur is 1/38416.
Probability that a wrong combination will occur is 38415/38416.
The odds = probability that event will occur / probability that event will not occur = (1/38416) / (38415/38416) = 1/38415.
So, the answer is 1:38415.

2 4 6 8 posibiliti 1:56000

The odds are 1 in 245,000,000

The odds are 1 in 245,000,000

14*13*12*11=24024

if each number will be used only once in a set
It becomes 14 * 13 * 12 * 11 = 24024.
The probability of the lottery out is 1/24024.

if each number will be used more than once in a set
It becomes 14 * 14 * 14 * 14 = 38416.
The probability of the lottery out is 1/38416.

https://cryptotabbrowser.com/19322042